Answer
-3
Work Step by Step
We use Cramer's rule to find the determinant of the matrix. Doing this, we obtain:
$$ \det \begin{pmatrix}-1&-2&-3\\ 3&4&2\\ 0&1&2\end{pmatrix}\\ -1\cdot \det \begin{pmatrix}4&2\\ 1&2\end{pmatrix}-\left(-2\right)\det \begin{pmatrix}3&2\\ 0&2\end{pmatrix}-3\cdot \det \begin{pmatrix}3&4\\ 0&1\end{pmatrix}\\ -3$$
