## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(5,-8)$
Alphabetical order: $a$ on the horizontal axis, $b$ on the vertical. Graphing $b+2a=2$ Set $b=0 \Rightarrow a=1 \qquad$... $(1,0)$ Set $a=0 \Rightarrow b=2 \qquad$... $(0,2)$ Graphing $a=-3-b$ Set $b=0 \Rightarrow a=-3 \qquad$... $(-3,0)$ Set $a=0 \Rightarrow b=-3 \qquad$... $(0,-3)$ Graphically solving: $a=5,\ b=-8$. Checking:$\qquad \left\{\begin{array}{lll} -8+2(5) =2 & \Rightarrow & -8+10=2 \\ & & \\ 5=-3-(-8) & \Rightarrow & 5=-3+8 \end{array}\right.$ both equations are satisfied, $(5,-8)$ is the solution.