Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 7 - Functions and Graphs - Review Exercises: Chapter 7 - Page 496: 24


$C(t)= 30t+90$, $7$ months

Work Step by Step

Let $t$ = months of membeship. Then $C(t)= 30t+90$ and the t for which $C(t)=300$ is found from $300= 30t+90\qquad$ ... subtract 90 $ 210=30t\qquad$ ... divide with 30 $t=7$ months
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