Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 7 - Functions and Graphs - 7.5 Formulas, Applications, and Variation - 7.5 Exercise Set - Page 486: 30



Work Step by Step

Use the rule $\frac{a}{b}=\frac{c}{d}\longrightarrow ad=bc$ to obtain: $$S(1-r)=a-ar^n$$ Factor out $a$ to obtain: $$S(1-r)=a(1-r^n)$$ Divide $1-r^n$ to both sides: $$\frac{S(1-r)}{1-r^n}=\frac{a(1-r^n)}{1-r^n} \\\color{blue}{\frac{S(1-r)}{1-r^n}=a}$$
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