Answer
The answer is below.
Work Step by Step
We see the expression starts with $n(z)$. Thus, we see that $z$ is the independent variable and $n$ is the dependent variable.
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 7 - Functions and Graphs - 7.1 Introduction to Function - 7.1 Exercise Set - Page 451: 80
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