## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$$9\sqrt{3}$$
We are given the following equation: $$A\left(s\right)=\frac{\sqrt{3}}{4}s^2$$ Thus, when the side length is 6, it follows: $$\frac{\sqrt{3}}{4}\left(6^2\right)\\ \frac{\sqrt{3}\cdot \:6^2}{4}\\ 9\sqrt{3}$$