Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 6 - Rational Expressions and Equations - Test: Chapter 6 - Page 439: 6



Work Step by Step

Recall, one never divides by a fraction. Rather, if we want to divide by a fraction, we multiply by the reciprocal of the fraction. Recall, the reciprocal of a fraction is that fraction with the numerator and the denominator switched. Thus, we find: $$ \frac{4a^2+1}{4a^2-1}\times \frac{4a^2+4a+1}{4a^2}\\ \frac{\left(4a^2+1\right)\left(2a+1\right)^2}{\left(2a+1\right)\left(2a-1\right)\times \:4a^2}\\ \frac{\left(4a^2+1\right)\left(2a+1\right)}{4a^2\left(2a-1\right)}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.