Answer
$$2ab^2+4b-a$$
Work Step by Step
We divide the two terms by cancelling out common factors. Doing this, we obtain:
$$ \frac{6a^2b^3+12ab^2-3a^2b}{3ab}\\ \frac{3ba\left(2ab^2+4b-a\right)}{3ab}\\ 2ab^2+4b-a$$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 6 - Rational Expressions and Equations - 6.7 Applications Using Rational Equations and Proportions - 6.7 Exercise Set - Page 430: 70
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