Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 6 - Rational Expressions and Equations - 6.6 Rational Equations - 6.6 Exercise Set - Page 417: 57


Answers vary. An example is below.

Work Step by Step

Start with a normal equation, which has a given solution. For instance: $$ x+3=2 \\ x=-1$$ Then, divide both sides by an expression that makes the solution cause the denominator to be zero, as follows: $$ \frac{x+3}{x+1}=\frac{2}{x+1}$$ The solution to this equation would be -1, but since this makes the denominator zero, there is no solution.
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