Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 6 - Rational Expressions and Equations - 6.5 Complex Rational Expressions - 6.5 Exercise Set - Page 409: 50

Answer

$$\frac{x^2-3x-2}{x^2-4x-3}$$

Work Step by Step

In order to simplify complex fractions, we first simplify the numerator and the denominator. Next, we multiply the numerator and the denominator by the reciprocal of the denominator and simplify. Doing this, we find: $$ \frac{\frac{x^2-3x-2}{x}}{\frac{x^2-4x-3}{x}}\\ \frac{\left(x^2-3x-2\right)x}{x\left(x^2-4x-3\right)}\\ \frac{x^2-3x-2}{x^2-4x-3}$$
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