Answer
$$\frac{4x^2-1}{x-5}$$
Work Step by Step
Recall, one never divides by a fraction. Rather, if we want to divide by a fraction, we multiply by the reciprocal of the fraction. Recall, the reciprocal of a fraction is that fraction with the numerator and the denominator switched. Thus, we find:
$$ \frac{\left(2x-1\right)\left(4x^2-1\right)}{2x^2-11x+5}\\ \frac{\left(2x-1\right)\left(4x^2-1\right)}{\left(2x-1\right)\left(x-5\right)}\\ \frac{4x^2-1}{x-5}$$
