## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 6 - Rational Expressions and Equations - 6.2 Multiplication and Division - 6.2 Exercise Set - Page 384: 27

#### Answer

$$\frac{7\left(a+3\right)}{a\left(a+4\right)}$$

#### Work Step by Step

To multiply fractions, we multiply the numerators by each other to get the new numerator, and we multiply the denominators by each other to get the new denominator. Doing this and simplifying, we find: $$\frac{a^2-9}{a^2}\cdot \frac{7a}{a^2+a-12}\\ \frac{7\left(a+3\right)\left(a-3\right)}{a\left(a-3\right)\left(a+4\right)}\\ \frac{7\left(a+3\right)}{a\left(a+4\right)}$$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.