Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 6 - Rational Expressions and Equations - 6.1 Rational Expressions - 6.1 Exercise Set - Page 379: 6



Work Step by Step

Let us solve the given problem in the following way: $(2t-1)(3t+4)=0$ This can be written as : $2t-1=0$ or, $3t+4=0$ Thus, $t=\dfrac{1}{2},\dfrac{-4}{3}$ Hence, the final answer will be $(c)$.
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