## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$$x=-1,\:x=\frac{8}{3}$$
We are asked to find the x intercepts. Thus, we first make sure the equation is set equal to zero and factor as necessary. Next, since there is 0 on one side of the equation, we set all of the factors equal to zero to solve. Doing this, we find: $$0=3x^2-5x-8\\ 0=3x\left(x+1\right)-8\left(x+1\right) \\ 0=\left(x+1\right)\left(3x-8\right) \\ x=-1,\:x=\frac{8}{3}$$