Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - Review Exercises: Chapter 5 - Page 369: 5

Answer

False

Work Step by Step

Consider the following equation: $$ x^2+4x+4$$ This factors to: $$ (x+2)^2$$ Thus, this equation will have only one solution, so not all quadratic equations have two solutions.
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