Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - Mid-Chapter Review - Mixed Review - Page 335: 18

Answer

$10(c+1)^2$

Work Step by Step

Factoring the negative $GCF= 10 ,$ the given expression is equivalent to \begin{array}{l}\require{cancel} 10c^2+20c+10 \\\\= 10(c^2+2c+1) .\end{array} Using the factoring of trinomials in the form $x^2+bx+c,$ the $\text{ expression }$ \begin{array}{l}\require{cancel} 10(c^2+2c+1) \end{array} has $c= 1 $ and $b= 2 .$ The two numbers with a product of $c$ and a sum of $b$ are $\left\{ 1,1 \right\}.$ Using these two numbers, the $\text{ expression }$ above is equivalent to \begin{array}{l}\require{cancel} 10(c+1)(c+1) \\\\= 10(c+1)^2 .\end{array}
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