Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.8 Solving Applications - 5.8 Exercise Set - Page 360: 24

Answer

$$H=300$$

Work Step by Step

We are given the following equation: $$ H=\frac{1}{2}(n^2-n)$$ Plugging in $25$ for $n$, we find: $$H=\frac{1\cdot \left(25^2-25\right)}{2} \\ H=\frac{600}{2} \\ H=300$$
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