Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.8 Solving Applications - 5.8 Exercise Set - Page 359: 10


The two integers are 13 and 15.

Work Step by Step

Note, the 5 step process is as follows: (1) Familiarize yourself with the problem. (2) Translate the problem into Algebra. (3) Solve. (4) Check. Note, if we want to check a solution, we would plug it back into the equation and check that the equation yields a true statement. (5) State the answer. After becoming familiar with the problem, we find: $$x\left(x+2\right)=195 \\ x^2+2x-195=0 \\ x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-195\right)}}{2\cdot \:1} \\ x=13,\:x=-15$$ The two integers are 13 and 15.
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