## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 5 - Polynomials and Factoring - 5.7 Solving Quadratic Equations by Factoring - 5.7 Exercise Set - Page 352: 40

#### Answer

$x=\left\{ 0,4 \right\}$

#### Work Step by Step

Factoring the given equation, $12t=3t^2 ,$ results to \begin{array}{l}\require{cancel} -3t^2+12t=0 \\\\ -3t(t-4)=0 .\end{array} Equating each factor to zero (Zero Product Principle), then the solutions to the equation, $-3t(t-4)=0 ,$ are \begin{array}{l}\require{cancel} -3t=0 \\\\ t=\dfrac{0}{-3} \\\\ t=0 ,\\\\\text{OR}\\\\ t-4=0 \\\\ t=4 .\end{array} Hence, $x=\left\{ 0,4 \right\} .$

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