Answer
$-2(a+1)^n(a+3)^2
(a+6)$
Work Step by Step
Factoring the $GCF=
(a+1)^n(a+3)^2
,$ the given expression is equivalent to
\begin{array}{l}\require{cancel}
3(a+1)^{n+1}(a+3)^2-5(a+1)^n(a+3)^3
\\\\=
(a+1)^n(a+3)^2
[3(a+1)-5(a+3)]
\\\\=
(a+1)^n(a+3)^2
[3(a)+3(1)-5(a)-5(3)]
\\\\=
(a+1)^n(a+3)^2
[3a+3-5a-15]
\\\\=
(a+1)^n(a+3)^2
[-2a-12]
\\\\=
(a+1)^n(a+3)^2
(-2)(a+6)
\\\\=
-2(a+1)^n(a+3)^2
(a+6)
.\end{array}