Answer
$x^3-2x^2-x+2$
Work Step by Step
Distribute each term of the binomial to obtain:
$=x(x^2-x-2)-1(x^2-x-2)$
Distribute $x$ and $1$ to obtain
$=x(x^2)-x(x)-x(2)-1(x^2)-1(-x)-1(-2)
\\=x^3-x^2-2x-x^2-(-x)-(-2)
\\=x^3-x^2-2x-x^2+x+2$
Combine like terms to obtain:
$=x^3+(-x^2-x^2)+(-2x+x)+2
\\=x^3+(-2x^2)+(-x)+2
\\=x^3-2x^2-x+2$
