Answer
$81a^4-1$
Work Step by Step
Use the formula $(a+b)(a-b)$ to multiply the last 2 factors to obtain:
$=(9a^2+1)[(3a)^2-1^2]
\\=(9a^2+1)(9a^2-1)$
Use the same formula again with $a=9a^2$ and $b=1$ to obtain:
$=(9a^2)^2-1^2
\\=81a^4-1$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set - Page 278: 108
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