## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$y-6=\frac{1}{4}(x+1)$
RECALL: The point-slope form of a line's equation is $y-y_1=m(x-x_1)$, where $m$=slope and $(x_1, y_1)$ is a point on the line. The given line has a slope of $\frac{1}{4}$ and contains the point $(-1, 6)$. Thus, the point-slope form of its equation is: $y-6=\frac{1}{4}[x-(-1)] \\y-6=\frac{1}{4}(x+1)$