## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 3 - Introduction to Graphing - Review Exercises: Chapter 3 - Page 225: 34

#### Answer

Refer to the graph below. #### Work Step by Step

RECALL: The point-slope form of a line's equation is $y-y_1=m(x-x_1)$ where $m$=slope and $(x_1, y_1)$ is a point on the line. The given equation can be written as: $y-(-2)=-\frac{1}{2}(x-3)$ Thus, it has a slope of $-\frac{1}{2}$ and contains the point $(3, -2)$. To graph this equation, perform the following steps: (1) Plot the point $(3, -2)$ (2) Use the slope to plot another point. From $(3, -2)$, move 1 unit down (the rise) and 2 units to the right (the run) to reach the point $(5, -3)$. Plot $(5, -3)$. (3) Connect the two points using a line to complete the graph. (Refer to the graph in the answer part above.)

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