Chapter 3 - Introduction to Graphing - 3.7 Point-Slope Form and Equations of Lines - 3.7 Exercise Set - Page 220: 90

$n=\dfrac{11}{2}$

Multiplying both sides by the $LCD=6$, the solution to the given equation, $ \dfrac{1}{2}n-\dfrac{1}{3}=\dfrac{1}{6}n+\dfrac{3}{2} $, is \begin{array}{l}\require{cancel} 3(1n)-2(1)=1(1n)+3(3) \\\\ 3n-2=n+9 \\\\ 3n-n=9+2 \\\\ 2n=11 \\\\ n=\dfrac{11}{2} .\end{array}