Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.4 Rates - 3.4 Exercise Set: 52

Answer

$\dfrac{1}{3}$

Work Step by Step

RECALL: $|a| = a$ if $a \ge 0$ $|a| = -a$ if $a \lt 0$ Using the definition above gives: $\left|-\frac{1}{3}\right|=-(\frac{-1}{3})=\frac{1}{3}$
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