## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 3 - Introduction to Graphing - 3.3 Graphing and Intercepts - 3.3 Exercise Set - Page 179: 58

#### Answer

x-intercept: $(0, 0)$ y-intercept: $(0, 0)$ Refer to the graph below. #### Work Step by Step

To find the x-intercept, set y=0, then solve for $x$: $x+2y=0 \\x+2(0)=0 \\x+0=0 \\x=0$ Thus, the x-intercept is $(0, 0)$. To find the y-intercept, set x=0, then solve for $y$: $x+2y=0 \\0+2y=0 \\2y=0 \\\frac{2y}{2}=\frac{0}{2} \\y=0$ Thus, the y-intercept is $(0, 0)$. Since the x and y-intercepts are the same, one more point is needed to graph the line. Let $x=2$ then solve for $y$: $x+2y=0 \\2+2y=0 \\2y=-2 \\\frac{2y}{2}=\frac{-2}{2} \\y=-1$ The point is $(2, -1)$. Plot the intercept $(0, 0)$ and the point $(2, -1)$ on the same coordinate plane, then connect the two points using a line. Refer to the attached image in the answer part above for the graph.

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