## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$3$
Distribute $3$ then combine like terms: $5x+3(2)-3(x)=12 \\5x+6-3x=12 \\(5x-3x)+6=12 \\2x+6=12$ Subtract $6$ to both sides of the equation: $2x+6-6=12-6 \\2x=6$ Divide $2$ to both sides of the equation: $\frac{2x}{2}=\frac{6}{2} \\x=3$ Check: $5x+3(2-x)=12 \\5(3) + 3(2-3)=12 \\15+3(-1)=12 \\15+(-3)=12 \\12=12$ Therefore, the solution to the given equation is $\color{blue}{3}$.