Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.2 Graphing Linear Equations - 3.2 Exercise Set - Page 171: 61



Work Step by Step

Distribute $3$ then combine like terms: $5x+3(2)-3(x)=12 \\5x+6-3x=12 \\(5x-3x)+6=12 \\2x+6=12$ Subtract $6$ to both sides of the equation: $2x+6-6=12-6 \\2x=6$ Divide $2$ to both sides of the equation: $\frac{2x}{2}=\frac{6}{2} \\x=3$ Check: $5x+3(2-x)=12 \\5(3) + 3(2-3)=12 \\15+3(-1)=12 \\15+(-3)=12 \\12=12$ Therefore, the solution to the given equation is $\color{blue}{3}$.
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