## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 3 - Introduction to Graphing - 3.2 Graphing Linear Equations - 3.2 Exercise Set - Page 170: 47

#### Answer

Refer to the graph below.

#### Work Step by Step

Solve for y. Subtract 2x to both sides: $6y+2x−2x=8−2x \\6y=8−2x$ Divide 6 to both sides: $\dfrac{6y}{6}=\dfrac{8−2x}{6} \\y=\dfrac{8}{6}−\dfrac{2x}{6} \\y=\dfrac{4}{3}−\dfrac{1}{3}x \\y=−\dfrac{1}{3}x+\dfrac{4}{3}$ Thus, the given equation is equivalent to $y=−\dfrac{1}{3}x+\dfrac{4}{3}$. To graph the equation, perform the following steps: (1) Create a table of values by assigning convenient values to x, then solve for the corresponding value of y for each value of x. (refer to the attached image below for the table) (2) Plot each point (or ordered pair) on the same coordinate plane, then connect the points using a straight line. (refer to the attached image in the answer part above for the final graph)

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