Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - Test: Chapter 2 - Page 151: 18


$r=\dfrac{A}{2\pi h}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given equation, $ A=2\pi rh, $ for $ r ,$ use properties of equality to isolate the variable. $\bf{\text{Solution Details:}}$ Using the properties of equality to isolate the variable, the equation above is equivalent to \begin{array}{l}\require{cancel} A=2\pi rh \\\\ \dfrac{A}{2\pi h}=\dfrac{2\pi rh}{2\pi h} \\\\ \dfrac{A}{2\pi h}=r \\\\ r=\dfrac{A}{2\pi h} .\end{array}
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