Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - Study Summary - Practice Exercises: 5

Answer

$c=\dfrac{d}{a-b}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given equation, $ ac-bc=d, $ for $ c ,$ use the Distributive Property and the properties of equality to isolate the variable. $\bf{\text{Solution Details:}}$ Using the Distributive Property which is given by $a(b+c)=ab+ac,$ the expression above is equivalent to \begin{array}{l}\require{cancel} ac-bc=d \\\\ c(a-b)=d .\end{array} Using the properties of equality to isolate the variable, the equation above is equivalent to \begin{array}{l}\require{cancel} c(a-b)=d \\\\ \dfrac{c(a-b)}{a-b}=\dfrac{d}{a-b} \\\\ c=\dfrac{d}{a-b} .\end{array}
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