Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.5 Problem Solving - 2.5 Exercise Set - Page 122: 14

Answer

The musher has traveled $699\displaystyle \frac{1}{3}$ miles.

Work Step by Step

$\bf{\text{l. Familiarize yourself with the problem.}}$ The start is at Anchorage. Letting Musher be x miles from Anchorage, it is $(1049-x)$ from Nome. We need to find an x such that $x$ is twice as much as $(1049-x).$ $\bf{\text{2. Translate to mathematical language. (This often means writing an equation.)}}$ $2(1049-x)=x$ $\bf{\text{3. Carry out some mathematical manipulation. (This often means solving an equation.)}}$ $ 2098-2x=x\qquad$ ... add $2x$ to both sides $ 2098=3x\qquad$ ... divide with 3 $699\displaystyle \frac{1}{3}=x$ $\bf{\text{4. Check your possible answer in the original problem.}}$ The distance to Nome is $1049-699\displaystyle \frac{1}{3}=349\frac{2}{3}.$ Double this, and we get $698\displaystyle \frac{4}{3}=699\frac{1}{3}$, the distance from Anchorage, as it should be. $\bf{\text{5. State the answer clearly using a complete sentence.}}$ The musher has traveled $699\displaystyle \frac{1}{3}$ miles.
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