Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.4 Applications with Percent - 2.4 Exercise Set - Page 111: 96

Answer

$5 \text{ ft. 6.35 in.}$

Work Step by Step

If at the age of $10$ Dana has reached $84.4 \%$ of her adult height and Dana's height now is $4$ ft. and $8$ in. Convert her height at the age of $10$ in inches ($1$ ft $= 12$ in.): $4\cdot 12+8=56$ Therefore we have: $\text{Adult height} = \text{height}\dfrac{100\%}{84.4\%}=56 \text{ in.} \dfrac{100\%}{84.4\%}\approx 66.35 \text{ in.}$ Convert to feet: $\text{Adult height} = \dfrac{66.35}{12}=5 \text{ ft. 6.35 in.}$
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