Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$20\%$ were sport utility vehicles $80\%$ were other types of vehicles.
Typical percentage problem: What percent ($n$, as a decimal number) of (the base amount $y$) is $x?$ Translated:$\quad n\cdot y=x$ --- Here, What percent ($n$, as a decimal number) of ($y=1,500,000$) is ($x=300,000$)$?$ Translated:$\quad n\cdot 1,500,000=300,000$ ... divide with $1,500,000$ $y=0.2\qquad$ .... convert to percent notation, (move the decimal point two places to the right and write a percent symbol.) $=20\%$ were sport utility vehicles $100\%-20\%=80\%$ were other types of vehicles.