## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$2.5$
Typical percentage problem: What percent ($n$, as a decimal number) of (the base amount $y)$ is $x?$ Translated:$\quad n\cdot y=x$ --- Here, reworded, $12\%$ of ($y=?$) is ($x=0.3$)$?$ Translated:$\quad 0.12\cdot y=0.3$ ($12\%$ converted to decimal notation is $0.12)$ ... divide the last equation with $0.12$ $y=\displaystyle \frac{0.3}{0.12}=2.5$