Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.3 Formulas - 2.3 Exercise Set - Page 102: 72



Work Step by Step

Using the properties of equality, in terms of $ y $, the given expression, $ \dfrac{y}{z}\div\dfrac{z}{t}=1 $, is equivalent to \begin{array}{l} \dfrac{y}{z}\cdot\dfrac{t}{z}=1 \\\\ \dfrac{yt}{z^2}=1 \\\\ \dfrac{z^2}{t}\cdot\dfrac{yt}{z^2}=1\cdot\dfrac{z^2}{t} \\\\ y=\dfrac{z^2}{t} .\end{array}
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