Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - Test: Chapter 14 - Page 929: 2

Answer

General term of the sequence is $\frac{4}{{{3}^{n}}}$.

Work Step by Step

The numerator in the sequence is the same for all terms, which is 4, and the denominator is the pattern as a power of 3. $\frac{4}{3},\frac{4}{9},\frac{4}{27},\ldots =\frac{4}{{{\left( 3 \right)}^{1}}},\frac{4}{{{\left( 3 \right)}^{2}}},\frac{4}{{{\left( 3 \right)}^{3}}},\ldots $ Thus, the general term of the sequence $\frac{4}{3},\frac{4}{9},\frac{4}{27},......$ is$\frac{4}{{{3}^{n}}}$.
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