Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - Review Exercises: Chapter 14 - Page 928: 36

Answer

$903$ poles.

Work Step by Step

There are $41$ poles in the second row, $40$ poles in the third row, and so on, ending with $1$ pole in the top row. To go from 42 poles in the bottom layer to one pole in the top layer, where each layer has 1 pole less than the layer below it, there must be 42 layers. Thus: ${{a}_{42}}=1$ and the number of terms is $n=42$. The sum of $n\text{th}$term of the arithmetic series is given by: ${{s}_{n}}=\frac{n}{2}\left( {{a}_{1}}+{{a}_{n}} \right)$ Where, ${{a}_{1}}=$first term and ${{a}_{n}}=$$n\text{th}$ term or last term Substitute the value of ${{a}_{1}}=42$, ${{a}_{n}}=1$ and $n=42$ in the equation ${{s}_{n}}=\frac{n}{2}\left( {{a}_{1}}+{{a}_{n}} \right)$ $\begin{align} & {{s}_{n}}=\frac{n}{2}\left( {{a}_{1}}+{{a}_{n}} \right) \\ & {{s}_{42}}=\frac{42}{2}\left( 42+1 \right) \\ & =21\times 43 \\ & =903 \end{align}$ Thus, the number of poles in the stack is $903$ poles.
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