Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 13 - Conic Sections - 13.3 Conic Sections: Hyperbolas - 13.3 Exercise Set - Page 871: 2


The vertex is $\left( 2,-1 \right)$ and axis of symmetry is $y=-1$.

Work Step by Step

$\begin{align} & x={{y}^{2}}+2y+1+2 \\ & ={{y}^{2}}+y+y+1+2 \\ & =y\left( y+1 \right)+1\left( y+1 \right)+2 \\ & =\left( y+1 \right)\left( y+1 \right)+2 \end{align}$ Further simplify, $x={{\left( y+1 \right)}^{2}}+2$ Compare it with the standard equation of a parabola, $a=1,h=2$ and $k=-1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.