Answer
No solution!
Work Step by Step
We have to solve $x^2+4x=60.$ Let's make the quadratic equation in its standard form as $ax^2+bx+c=0.$
$$x^2+4x-60=0.$$
Let's find the discriminant. $D=b^2-4ac.$ In our case
$$D=16-4\cdot1\cdot60=16-240=-222 < 0.$$
There is no real solution!
