Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Mid-Chapter Review - Mixed Review - Page 812: 16

Answer

$\quad \log_{64}16=2/3.$

Work Step by Step

For $x\gt 0$ and $a$, a positive constant other than 1, $\log_{a}x$ is the exponent to which $a$ must be raised in order to get $x$. Thus, $\log_{a}x=m$ means $a^{m}=x$ Here, $ 64^{2/3}=16 \quad$ means $\quad \log_{64}16=2/3.$
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