## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\quad \log_{64}16=2/3.$
For $x\gt 0$ and $a$, a positive constant other than 1, $\log_{a}x$ is the exponent to which $a$ must be raised in order to get $x$. Thus, $\log_{a}x=m$ means $a^{m}=x$ Here, $64^{2/3}=16 \quad$ means $\quad \log_{64}16=2/3.$