Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.5 Common Logarithms and Natural Logarithms - 12.5 Exercise Set - Page 819: 91



Work Step by Step

Apply $\log_{a}(MN)=\log_{a}M+\log_{a}N$ $\log 492+\log x=5.728\qquad$ ... subtract $\log 492$ $\log x=5.728-\log 492\qquad$ ... apply inverse function $10^{(...)}$ $x=10^{5.728-\log 492}\approx 1086.5129256$ To four decimal places, $x=1086.5129$
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