## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\displaystyle \log_{a}(\frac{P}{Q})^{x}=\qquad$ ... apply $\log_{a}M^{p}=p\cdot\log_{a}M$ $=x\displaystyle \log_{a}(\frac{P}{Q})\qquad$ ... apply $\displaystyle \log_{a}\frac{M}{N}=\log_{a}M-\log_{a}N$ $=x[\log_{a}P-\log_{a}Q]$ $=x\log_{a}P-\fbox{$x$}\log_{a}Q$