Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.3 Logarithmic Functions - 12.3 Exercise Set - Page 804: 112

Answer

$1$

Work Step by Step

By definition, $\log_{4}256=x$ means $x$ is the exponent with which we raise ($4$) to obtain $256.$ $4^{4}=256 \Rightarrow \log_{4}256=4$ So, $\log_{2}(\log_{2}(\log_{4}256))=\log_{2}(\log_{2}(4))$ By definition, $\log_{2}(4)=x$ means $x$ is the exponent with which we raise ($2$) to obtain $4.$ $2^{2}=4 \Rightarrow \log_{2}(4)=2$ So, $\log_{2}(\log_{2}(\log_{4}256))=$ $=\log_{2}(\log_{2}(4))$ $=\log_{2}(2)$ $=1$, because $2^{1}=2$ (so $\log_{2}(2)=1)$
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