Answer
$(h)$
Work Step by Step
The logarithm, base $a$, of 1 is 0$:\qquad \log_{a} 1=0.$
Or,
$m=\log_{a}x$ is equivalent to $a^{m}=x.$
so
$2^{0}=1 \Leftrightarrow \log_{2}1=0$
case $(h)$
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