## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$f(x)=x^{4},\ \quad g(x)=3x-5$
$h(x)$ equals the 4th power of (the difference of 3x and 5) So if we define $g(x)$ as (the difference of 3x and 5) and $f(x)$ as the (4th power of x) then $h(x)=f[g(x)]=(f\circ g)(x).$ $f(x)=x^{4},\ \quad g(x)=3x-5$