Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.1 Quadratic Equations - 11.1 Exercise Set - Page 706: 34

Answer

The solutions are $x=-3$ or $x=7$.

Work Step by Step

$g(x)=(x-2)^{2}$ $ g(x)=25\qquad$...substitute $25$ for $g(x)$ $(x-2)^{2}=25$ According to the general principle of square roots: For any real number $k$ and any algebraic expression $x$ : $\text{If }x^{2}=k,\text{ then }x=\sqrt{k}\text{ or }x=-\sqrt{k}$. $ x-2=\pm\sqrt{25}\qquad$...add $2$ to each side. $ x-2+2=\pm\sqrt{25}+2\qquad$...simplify. $x=2\pm 5$ $x=2+5$ or $x=2-5$ $x=7$ or $x=-3$
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