Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Study Summary - Practice Exercises: 15

Answer

$\sqrt{51}\approx7.141 \text{ }m$

Work Step by Step

Let the right triangle have $a$ and $b$ as the legs and $c$ as the hypotenuse. Using $a^2+b^2=c^2$ or the Pythagorean Theorem, with $ c=10 $ and $ a=7 ,$ then \begin{array}{l}\require{cancel} a^2+b^2=c^2 \\\\ 7^2+b^2=10^2 \\\\ 49+b^2=100 \\\\ b^2=100-49 \\\\ b^2=51 \\\\ b=\sqrt{51} .\end{array} Hence, the other leg is $ \sqrt{51}\approx7.141 \text{ }m $ long.
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