## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 10 - Exponents and Radicals - Study Summary - Practice Exercises - Page 690: 3

#### Answer

$6|x|$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$ Use the properties of radicals to simplify the given expression, $\sqrt[]{36x^2} .$ $\bf{\text{Solution Details:}}$ Using $\sqrt[n]{x^n}=|x|$ if $n$ is even and $\sqrt[n]{x^n}=x$ if $n$ is odd, then \begin{array}{l}\require{cancel} \sqrt[]{36x^2} \\\\= \sqrt[]{(6x)^2} \\\\= |6x| \\\\= |6|\cdot|x| \\\\= 6|x| .\end{array}

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