Answer
$i$
Work Step by Step
Using $i^2=-1$ and the laws of exponents, the given expression, $
i^{17}
,$ is equivalent to
\begin{array}{l}\require{cancel}
i^{16}\cdot i
\\\\=
\left( i^2 \right)^{8}\cdot i
\\\\=
\left( -1 \right)^{8}\cdot i
\\\\=
1\cdot i
\\\\=
i
\end{array}